Metamath Proof Explorer


Theorem lestric

Description: Surreal trichotomy law. (Contributed by Scott Fenton, 14-Feb-2025)

Ref Expression
Assertion lestric ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 ≤s 𝐵 ∨ 𝐵 ≤s 𝐴 ) )

Proof

Step Hyp Ref Expression
1 ltsasym ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( 𝐵 <s 𝐴 → ¬ 𝐴 <s 𝐵 ) )
2 ltnles ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( 𝐵 <s 𝐴 ↔ ¬ 𝐴 ≤s 𝐵 ) )
3 2 bicomd ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( ¬ 𝐴 ≤s 𝐵 ↔ 𝐵 <s 𝐴 ) )
4 lenlts ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( 𝐵 ≤s 𝐴 ↔ ¬ 𝐴 <s 𝐵 ) )
5 1 3 4 3imtr4d ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( ¬ 𝐴 ≤s 𝐵 → 𝐵 ≤s 𝐴 ) )
6 5 orrd ⊢ ( ( 𝐵 ∈ No ∧ 𝐴 ∈ No ) → ( 𝐴 ≤s 𝐵 ∨ 𝐵 ≤s 𝐴 ) )
7 6 ancoms ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 ≤s 𝐵 ∨ 𝐵 ≤s 𝐴 ) )