Theorem lgsval4lem

Description: Lemma for lgsval4 . (Contributed by Mario Carneiro, 4-Feb-2015)

	Ref	Expression
Hypothesis	lgsval.1	⊢ 𝐹 = ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) )
Assertion	lgsval4lem	⊢ ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) → 𝐹 = ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( ( 𝐴 /L 𝑛 ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) ) )

Proof

Step	Hyp	Ref	Expression
1		lgsval.1	⊢ 𝐹 = ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) )
2		eqid	⊢ ( 𝑚 ∈ ℕ ↦ if ( 𝑚 ∈ ℙ , ( if ( 𝑚 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑚 − 1 ) / 2 ) ) + 1 ) mod 𝑚 ) − 1 ) ) ↑ ( 𝑚 pCnt 𝑛 ) ) , 1 ) ) = ( 𝑚 ∈ ℕ ↦ if ( 𝑚 ∈ ℙ , ( if ( 𝑚 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑚 − 1 ) / 2 ) ) + 1 ) mod 𝑚 ) − 1 ) ) ↑ ( 𝑚 pCnt 𝑛 ) ) , 1 ) )
3	2	lgsval2lem	⊢ ( ( 𝐴 ∈ ℤ ∧ 𝑛 ∈ ℙ ) → ( 𝐴 /L 𝑛 ) = if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) )
4	3	3ad2antl1	⊢ ( ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ∧ 𝑛 ∈ ℙ ) → ( 𝐴 /L 𝑛 ) = if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) )
5	4	oveq1d	⊢ ( ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ∧ 𝑛 ∈ ℙ ) → ( ( 𝐴 /L 𝑛 ) ↑ ( 𝑛 pCnt 𝑁 ) ) = ( if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) ↑ ( 𝑛 pCnt 𝑁 ) ) )
6	5	ifeq1da	⊢ ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) → if ( 𝑛 ∈ ℙ , ( ( 𝐴 /L 𝑛 ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) = if ( 𝑛 ∈ ℙ , ( if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) )
7	6	mpteq2dv	⊢ ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) → ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( ( 𝐴 /L 𝑛 ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) ) = ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( if ( 𝑛 = 2 , if ( 2 ∥ 𝐴 , 0 , if ( ( 𝐴 mod 8 ) ∈ { 1 , 7 } , 1 , - 1 ) ) , ( ( ( ( 𝐴 ↑ ( ( 𝑛 − 1 ) / 2 ) ) + 1 ) mod 𝑛 ) − 1 ) ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) ) )
8	1 7	eqtr4id	⊢ ( ( 𝐴 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) → 𝐹 = ( 𝑛 ∈ ℕ ↦ if ( 𝑛 ∈ ℙ , ( ( 𝐴 /L 𝑛 ) ↑ ( 𝑛 pCnt 𝑁 ) ) , 1 ) ) )