Metamath Proof Explorer


Theorem lidrideqd

Description: If there is a left and right identity element for any binary operation (group operation) .+ , both identity elements are equal. Generalization of statement in Lang p. 3: it is sufficient that "e" is a left identity element and "e``" is a right identity element instead of both being (two-sided) identity elements. (Contributed by AV, 26-Dec-2023)

Ref Expression
Hypotheses lidrideqd.l ⊢ ( 𝜑 → 𝐿 ∈ 𝐵 )
lidrideqd.r ⊢ ( 𝜑 → 𝑅 ∈ 𝐵 )
lidrideqd.li ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐵 ( 𝐿 + 𝑥 ) = 𝑥 )
lidrideqd.ri ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐵 ( 𝑥 + 𝑅 ) = 𝑥 )
Assertion lidrideqd ( 𝜑 → 𝐿 = 𝑅 )

Proof

Step Hyp Ref Expression
1 lidrideqd.l ⊢ ( 𝜑 → 𝐿 ∈ 𝐵 )
2 lidrideqd.r ⊢ ( 𝜑 → 𝑅 ∈ 𝐵 )
3 lidrideqd.li ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐵 ( 𝐿 + 𝑥 ) = 𝑥 )
4 lidrideqd.ri ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐵 ( 𝑥 + 𝑅 ) = 𝑥 )
5 oveq1 ⊢ ( 𝑥 = 𝐿 → ( 𝑥 + 𝑅 ) = ( 𝐿 + 𝑅 ) )
6 id ⊢ ( 𝑥 = 𝐿 → 𝑥 = 𝐿 )
7 5 6 eqeq12d ⊢ ( 𝑥 = 𝐿 → ( ( 𝑥 + 𝑅 ) = 𝑥 ↔ ( 𝐿 + 𝑅 ) = 𝐿 ) )
8 7 4 1 rspcdva ⊢ ( 𝜑 → ( 𝐿 + 𝑅 ) = 𝐿 )
9 oveq2 ⊢ ( 𝑥 = 𝑅 → ( 𝐿 + 𝑥 ) = ( 𝐿 + 𝑅 ) )
10 id ⊢ ( 𝑥 = 𝑅 → 𝑥 = 𝑅 )
11 9 10 eqeq12d ⊢ ( 𝑥 = 𝑅 → ( ( 𝐿 + 𝑥 ) = 𝑥 ↔ ( 𝐿 + 𝑅 ) = 𝑅 ) )
12 11 3 2 rspcdva ⊢ ( 𝜑 → ( 𝐿 + 𝑅 ) = 𝑅 )
13 8 12 eqtr3d ⊢ ( 𝜑 → 𝐿 = 𝑅 )