Metamath Proof Explorer
Description: A deduction based on modus ponens. (Contributed by Mario Carneiro, 24-Dec-2016)
|
|
Ref |
Expression |
|
Hypotheses |
mp3and.1 |
⊢ ( 𝜑 → 𝜓 ) |
|
|
mp3and.2 |
⊢ ( 𝜑 → 𝜒 ) |
|
|
mp3and.3 |
⊢ ( 𝜑 → 𝜃 ) |
|
|
mp3and.4 |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) → 𝜏 ) ) |
|
Assertion |
mp3and |
⊢ ( 𝜑 → 𝜏 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
mp3and.1 |
⊢ ( 𝜑 → 𝜓 ) |
2 |
|
mp3and.2 |
⊢ ( 𝜑 → 𝜒 ) |
3 |
|
mp3and.3 |
⊢ ( 𝜑 → 𝜃 ) |
4 |
|
mp3and.4 |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) → 𝜏 ) ) |
5 |
1 2 3
|
3jca |
⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) ) |
6 |
5 4
|
mpd |
⊢ ( 𝜑 → 𝜏 ) |