Metamath Proof Explorer


Theorem mpjao3dan

Description: Eliminate a three-way disjunction in a deduction. (Contributed by Thierry Arnoux, 13-Apr-2018) (Proof shortened by Wolf Lammen, 20-Apr-2024)

Ref Expression
Hypotheses mpjao3dan.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
mpjao3dan.2 ⊢ ( ( 𝜑 ∧ 𝜃 ) → 𝜒 )
mpjao3dan.3 ⊢ ( ( 𝜑 ∧ 𝜏 ) → 𝜒 )
mpjao3dan.4 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜃 ∨ 𝜏 ) )
Assertion mpjao3dan ( 𝜑 → 𝜒 )

Proof

Step Hyp Ref Expression
1 mpjao3dan.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
2 mpjao3dan.2 ⊢ ( ( 𝜑 ∧ 𝜃 ) → 𝜒 )
3 mpjao3dan.3 ⊢ ( ( 𝜑 ∧ 𝜏 ) → 𝜒 )
4 mpjao3dan.4 ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜃 ∨ 𝜏 ) )
5 1 2 3 3jaodan ⊢ ( ( 𝜑 ∧ ( 𝜓 ∨ 𝜃 ∨ 𝜏 ) ) → 𝜒 )
6 4 5 mpdan ⊢ ( 𝜑 → 𝜒 )