Metamath Proof Explorer


Theorem msubty

Description: The type of a substituted expression is the same as the original type. (Contributed by Mario Carneiro, 18-Jul-2016)

Ref Expression
Hypotheses msubffval.v ⊢ 𝑉 = ( mVR ‘ 𝑇 )
msubffval.r ⊢ 𝑅 = ( mREx ‘ 𝑇 )
msubffval.s ⊢ 𝑆 = ( mSubst ‘ 𝑇 )
msubffval.e ⊢ 𝐸 = ( mEx ‘ 𝑇 )
Assertion msubty ( ( 𝐹 : 𝐴 ⟶ 𝑅 ∧ 𝐴 ⊆ 𝑉 ∧ 𝑋 ∈ 𝐸 ) → ( 1st ‘ ( ( 𝑆 ‘ 𝐹 ) ‘ 𝑋 ) ) = ( 1st ‘ 𝑋 ) )

Proof

Step Hyp Ref Expression
1 msubffval.v ⊢ 𝑉 = ( mVR ‘ 𝑇 )
2 msubffval.r ⊢ 𝑅 = ( mREx ‘ 𝑇 )
3 msubffval.s ⊢ 𝑆 = ( mSubst ‘ 𝑇 )
4 msubffval.e ⊢ 𝐸 = ( mEx ‘ 𝑇 )
5 eqid ⊢ ( mRSubst ‘ 𝑇 ) = ( mRSubst ‘ 𝑇 )
6 1 2 3 4 5 msubval ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝑅 ∧ 𝐴 ⊆ 𝑉 ∧ 𝑋 ∈ 𝐸 ) → ( ( 𝑆 ‘ 𝐹 ) ‘ 𝑋 ) = ⟨ ( 1st ‘ 𝑋 ) , ( ( ( mRSubst ‘ 𝑇 ) ‘ 𝐹 ) ‘ ( 2nd ‘ 𝑋 ) ) ⟩ )
7 fvex ⊢ ( 1st ‘ 𝑋 ) ∈ V
8 fvex ⊢ ( ( ( mRSubst ‘ 𝑇 ) ‘ 𝐹 ) ‘ ( 2nd ‘ 𝑋 ) ) ∈ V
9 7 8 op1std ⊢ ( ( ( 𝑆 ‘ 𝐹 ) ‘ 𝑋 ) = ⟨ ( 1st ‘ 𝑋 ) , ( ( ( mRSubst ‘ 𝑇 ) ‘ 𝐹 ) ‘ ( 2nd ‘ 𝑋 ) ) ⟩ → ( 1st ‘ ( ( 𝑆 ‘ 𝐹 ) ‘ 𝑋 ) ) = ( 1st ‘ 𝑋 ) )
10 6 9 syl ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝑅 ∧ 𝐴 ⊆ 𝑉 ∧ 𝑋 ∈ 𝐸 ) → ( 1st ‘ ( ( 𝑆 ‘ 𝐹 ) ‘ 𝑋 ) ) = ( 1st ‘ 𝑋 ) )