Metamath Proof Explorer
Description: Contrapositive inference for inequality. (Contributed by NM, 31-Jan-2008)
|
|
Ref |
Expression |
|
Hypothesis |
necon1bbid.1 |
⊢ ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) ) |
|
Assertion |
necon1bbid |
⊢ ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
necon1bbid.1 |
⊢ ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) ) |
2 |
|
df-ne |
⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝐴 = 𝐵 ) |
3 |
2 1
|
bitr3id |
⊢ ( 𝜑 → ( ¬ 𝐴 = 𝐵 ↔ 𝜓 ) ) |
4 |
3
|
con1bid |
⊢ ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) ) |