Metamath Proof Explorer


Theorem necon1bbid

Description: Contrapositive inference for inequality. (Contributed by NM, 31-Jan-2008)

Ref Expression
Hypothesis necon1bbid.1 ⊢ ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) )
Assertion necon1bbid ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 necon1bbid.1 ⊢ ( 𝜑 → ( 𝐴 ≠ 𝐵 ↔ 𝜓 ) )
2 df-ne ⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝐴 = 𝐵 )
3 2 1 bitr3id ⊢ ( 𝜑 → ( ¬ 𝐴 = 𝐵 ↔ 𝜓 ) )
4 3 con1bid ⊢ ( 𝜑 → ( ¬ 𝜓 ↔ 𝐴 = 𝐵 ) )