Metamath Proof Explorer


Theorem negcon1i

Description: Negative contraposition law. (Contributed by NM, 25-Aug-1999)

Ref Expression
Hypotheses negidi.1 𝐴 ∈ ℂ
pncan3i.2 𝐵 ∈ ℂ
Assertion negcon1i ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 )

Proof

Step Hyp Ref Expression
1 negidi.1 𝐴 ∈ ℂ
2 pncan3i.2 𝐵 ∈ ℂ
3 negcon1 ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 ) )
4 1 2 3 mp2an ( - 𝐴 = 𝐵 ↔ - 𝐵 = 𝐴 )