Metamath Proof Explorer


Theorem negs0s

Description: Negative surreal zero is surreal zero. (Contributed by Scott Fenton, 20-Aug-2024)

Ref Expression
Assertion negs0s ( -us ‘ 0s ) = 0s

Proof

Step Hyp Ref Expression
1 right0s ( R ‘ 0s ) = ∅
2 1 imaeq2i ( -us “ ( R ‘ 0s ) ) = ( -us “ ∅ )
3 ima0 ( -us “ ∅ ) = ∅
4 2 3 eqtri ( -us “ ( R ‘ 0s ) ) = ∅
5 left0s ( L ‘ 0s ) = ∅
6 5 imaeq2i ( -us “ ( L ‘ 0s ) ) = ( -us “ ∅ )
7 6 3 eqtri ( -us “ ( L ‘ 0s ) ) = ∅
8 4 7 oveq12i ( ( -us “ ( R ‘ 0s ) ) |s ( -us “ ( L ‘ 0s ) ) ) = ( ∅ |s ∅ )
9 0sno 0s ∈ No
10 negsval ( 0s ∈ No → ( -us ‘ 0s ) = ( ( -us “ ( R ‘ 0s ) ) |s ( -us “ ( L ‘ 0s ) ) ) )
11 9 10 ax-mp ( -us ‘ 0s ) = ( ( -us “ ( R ‘ 0s ) ) |s ( -us “ ( L ‘ 0s ) ) )
12 df-0s 0s = ( ∅ |s ∅ )
13 8 11 12 3eqtr4i ( -us ‘ 0s ) = 0s