Metamath Proof Explorer


Theorem nfeqd

Description: Hypothesis builder for equality. (Contributed by Mario Carneiro, 7-Oct-2016)

Ref Expression
Hypotheses nfeqd.1 ⊢ ( 𝜑 → Ⅎ 𝑥 𝐴 )
nfeqd.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝐵 )
Assertion nfeqd ( 𝜑 → Ⅎ 𝑥 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 nfeqd.1 ⊢ ( 𝜑 → Ⅎ 𝑥 𝐴 )
2 nfeqd.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝐵 )
3 dfcleq ⊢ ( 𝐴 = 𝐵 ↔ ∀ 𝑦 ( 𝑦 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
4 nfv ⊢ Ⅎ 𝑦 𝜑
5 df-nfc ⊢ ( Ⅎ 𝑥 𝐴 ↔ ∀ 𝑦 Ⅎ 𝑥 𝑦 ∈ 𝐴 )
6 1 5 sylib ⊢ ( 𝜑 → ∀ 𝑦 Ⅎ 𝑥 𝑦 ∈ 𝐴 )
7 6 19.21bi ⊢ ( 𝜑 → Ⅎ 𝑥 𝑦 ∈ 𝐴 )
8 df-nfc ⊢ ( Ⅎ 𝑥 𝐵 ↔ ∀ 𝑦 Ⅎ 𝑥 𝑦 ∈ 𝐵 )
9 2 8 sylib ⊢ ( 𝜑 → ∀ 𝑦 Ⅎ 𝑥 𝑦 ∈ 𝐵 )
10 9 19.21bi ⊢ ( 𝜑 → Ⅎ 𝑥 𝑦 ∈ 𝐵 )
11 7 10 nfbid ⊢ ( 𝜑 → Ⅎ 𝑥 ( 𝑦 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
12 4 11 nfald ⊢ ( 𝜑 → Ⅎ 𝑥 ∀ 𝑦 ( 𝑦 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
13 3 12 nfxfrd ⊢ ( 𝜑 → Ⅎ 𝑥 𝐴 = 𝐵 )