Metamath Proof Explorer


Theorem nfnf

Description: If x is not free in ph , then it is not free in F/ y ph . (Contributed by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 30-Dec-2017)

Ref Expression
Hypothesis nfnf.1 𝑥 𝜑
Assertion nfnf 𝑥𝑦 𝜑

Proof

Step Hyp Ref Expression
1 nfnf.1 𝑥 𝜑
2 df-nf ( Ⅎ 𝑦 𝜑 ↔ ( ∃ 𝑦 𝜑 → ∀ 𝑦 𝜑 ) )
3 1 nfex 𝑥𝑦 𝜑
4 1 nfal 𝑥𝑦 𝜑
5 3 4 nfim 𝑥 ( ∃ 𝑦 𝜑 → ∀ 𝑦 𝜑 )
6 2 5 nfxfr 𝑥𝑦 𝜑