Metamath Proof Explorer


Theorem noxpordfr

Description: Next we establish the foundedness of the relationship. (Contributed by Scott Fenton, 19-Aug-2024)

Ref Expression
Hypotheses noxpord.1 𝑅 = { ⟨ 𝑎 , 𝑏 ⟩ ∣ 𝑎 ∈ ( ( L ‘ 𝑏 ) ∪ ( R ‘ 𝑏 ) ) }
noxpord.2 𝑆 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ ( No × No ) ∧ 𝑦 ∈ ( No × No ) ∧ ( ( ( 1st𝑥 ) 𝑅 ( 1st𝑦 ) ∨ ( 1st𝑥 ) = ( 1st𝑦 ) ) ∧ ( ( 2nd𝑥 ) 𝑅 ( 2nd𝑦 ) ∨ ( 2nd𝑥 ) = ( 2nd𝑦 ) ) ∧ 𝑥𝑦 ) ) }
Assertion noxpordfr 𝑆 Fr ( No × No )

Proof

Step Hyp Ref Expression
1 noxpord.1 𝑅 = { ⟨ 𝑎 , 𝑏 ⟩ ∣ 𝑎 ∈ ( ( L ‘ 𝑏 ) ∪ ( R ‘ 𝑏 ) ) }
2 noxpord.2 𝑆 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ( 𝑥 ∈ ( No × No ) ∧ 𝑦 ∈ ( No × No ) ∧ ( ( ( 1st𝑥 ) 𝑅 ( 1st𝑦 ) ∨ ( 1st𝑥 ) = ( 1st𝑦 ) ) ∧ ( ( 2nd𝑥 ) 𝑅 ( 2nd𝑦 ) ∨ ( 2nd𝑥 ) = ( 2nd𝑦 ) ) ∧ 𝑥𝑦 ) ) }
3 1 lrrecfr 𝑅 Fr No
4 3 a1i ( ⊤ → 𝑅 Fr No )
5 2 4 4 frxp2 ( ⊤ → 𝑆 Fr ( No × No ) )
6 5 mptru 𝑆 Fr ( No × No )