Metamath Proof Explorer


Theorem nv0rid

Description: The zero vector is a right identity element. (Contributed by NM, 28-Nov-2007) (Revised by Mario Carneiro, 21-Dec-2013) (New usage is discouraged.)

Ref Expression
Hypotheses nv0id.1 ⊢ 𝑋 = ( BaseSet ‘ 𝑈 )
nv0id.2 ⊢ 𝐺 = ( +𝑣 ‘ 𝑈 )
nv0id.6 ⊢ 𝑍 = ( 0vec ‘ 𝑈 )
Assertion nv0rid ( ( 𝑈 ∈ NrmCVec ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 𝐺 𝑍 ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 nv0id.1 ⊢ 𝑋 = ( BaseSet ‘ 𝑈 )
2 nv0id.2 ⊢ 𝐺 = ( +𝑣 ‘ 𝑈 )
3 nv0id.6 ⊢ 𝑍 = ( 0vec ‘ 𝑈 )
4 2 3 0vfval ⊢ ( 𝑈 ∈ NrmCVec → 𝑍 = ( GId ‘ 𝐺 ) )
5 4 oveq2d ⊢ ( 𝑈 ∈ NrmCVec → ( 𝐴 𝐺 𝑍 ) = ( 𝐴 𝐺 ( GId ‘ 𝐺 ) ) )
6 5 adantr ⊢ ( ( 𝑈 ∈ NrmCVec ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 𝐺 𝑍 ) = ( 𝐴 𝐺 ( GId ‘ 𝐺 ) ) )
7 2 nvgrp ⊢ ( 𝑈 ∈ NrmCVec → 𝐺 ∈ GrpOp )
8 1 2 bafval ⊢ 𝑋 = ran 𝐺
9 eqid ⊢ ( GId ‘ 𝐺 ) = ( GId ‘ 𝐺 )
10 8 9 grporid ⊢ ( ( 𝐺 ∈ GrpOp ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 𝐺 ( GId ‘ 𝐺 ) ) = 𝐴 )
11 7 10 sylan ⊢ ( ( 𝑈 ∈ NrmCVec ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 𝐺 ( GId ‘ 𝐺 ) ) = 𝐴 )
12 6 11 eqtrd ⊢ ( ( 𝑈 ∈ NrmCVec ∧ 𝐴 ∈ 𝑋 ) → ( 𝐴 𝐺 𝑍 ) = 𝐴 )