Metamath Proof Explorer


Theorem nvof1ob

Description: A class equal to its converse is a function on a class if and only if it is a bijection from that class onto itself (the reverse implication holds without the hypothesis, see f1ofn ). (Contributed by BJ, 8-Nov-2026) Can shorten nvof1o using biimpac .

Ref Expression
Assertion nvof1ob ( ◡ 𝐹 = 𝐹 → ( 𝐹 Fn 𝐴 ↔ 𝐹 : 𝐴 ⟶1-1onto 𝐴 ) )

Proof

Step Hyp Ref Expression
1 dff1o4 ⊢ ( 𝐹 : 𝐴 ⟶1-1onto 𝐴 ↔ ( 𝐹 Fn 𝐴 ∧ ◡ 𝐹 Fn 𝐴 ) )
2 fneq1 ⊢ ( ◡ 𝐹 = 𝐹 → ( ◡ 𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐴 ) )
3 2 anbi2d ⊢ ( ◡ 𝐹 = 𝐹 → ( ( 𝐹 Fn 𝐴 ∧ ◡ 𝐹 Fn 𝐴 ) ↔ ( 𝐹 Fn 𝐴 ∧ 𝐹 Fn 𝐴 ) ) )
4 1 3 bitrid ⊢ ( ◡ 𝐹 = 𝐹 → ( 𝐹 : 𝐴 ⟶1-1onto 𝐴 ↔ ( 𝐹 Fn 𝐴 ∧ 𝐹 Fn 𝐴 ) ) )
5 anidm ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐹 Fn 𝐴 ) ↔ 𝐹 Fn 𝐴 )
6 4 5 bitr2di ⊢ ( ◡ 𝐹 = 𝐹 → ( 𝐹 Fn 𝐴 ↔ 𝐹 : 𝐴 ⟶1-1onto 𝐴 ) )