Metamath Proof Explorer


Theorem orbi1d

Description: Deduction adding a right disjunct to both sides of a logical equivalence. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypothesis bid.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion orbi1d ( 𝜑 → ( ( 𝜓 ∨ 𝜃 ) ↔ ( 𝜒 ∨ 𝜃 ) ) )

Proof

Step Hyp Ref Expression
1 bid.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 1 orbi2d ⊢ ( 𝜑 → ( ( 𝜃 ∨ 𝜓 ) ↔ ( 𝜃 ∨ 𝜒 ) ) )
3 orcom ⊢ ( ( 𝜓 ∨ 𝜃 ) ↔ ( 𝜃 ∨ 𝜓 ) )
4 orcom ⊢ ( ( 𝜒 ∨ 𝜃 ) ↔ ( 𝜃 ∨ 𝜒 ) )
5 2 3 4 3bitr4g ⊢ ( 𝜑 → ( ( 𝜓 ∨ 𝜃 ) ↔ ( 𝜒 ∨ 𝜃 ) ) )