Description: Deduce implication from disjunction. (Contributed by NM, 18-May-1994)
| Ref | Expression | ||
|---|---|---|---|
| Hypothesis | ord.1 | ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) ) | |
| Assertion | ord | ⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ord.1 | ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) ) | |
| 2 | df-or | ⊢ ( ( 𝜓 ∨ 𝜒 ) ↔ ( ¬ 𝜓 → 𝜒 ) ) | |
| 3 | 1 2 | sylib | ⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |