Metamath Proof Explorer


Theorem ordtri2or2

Description: A trichotomy law for ordinal classes. (Contributed by NM, 2-Nov-2003)

Ref Expression
Assertion ordtri2or2 ( ( Ord 𝐴 ∧ Ord 𝐵 ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 ordtri2or ⊢ ( ( Ord 𝐴 ∧ Ord 𝐵 ) → ( 𝐴 ∈ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) )
2 ordelss ⊢ ( ( Ord 𝐵 ∧ 𝐴 ∈ 𝐵 ) → 𝐴 ⊆ 𝐵 )
3 2 ex ⊢ ( Ord 𝐵 → ( 𝐴 ∈ 𝐵 → 𝐴 ⊆ 𝐵 ) )
4 3 orim1d ⊢ ( Ord 𝐵 → ( ( 𝐴 ∈ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) ) )
5 4 adantl ⊢ ( ( Ord 𝐴 ∧ Ord 𝐵 ) → ( ( 𝐴 ∈ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) ) )
6 1 5 mpd ⊢ ( ( Ord 𝐴 ∧ Ord 𝐵 ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) )