Metamath Proof Explorer


Theorem ovmpog

Description: Value of an operation given by a maps-to rule. Special case. (Contributed by NM, 14-Sep-1999) (Revised by David Abernethy, 19-Jun-2012)

Ref Expression
Hypotheses ovmpog.1 ⊢ ( 𝑥 = 𝐴 → 𝑅 = 𝐺 )
ovmpog.2 ⊢ ( 𝑦 = 𝐵 → 𝐺 = 𝑆 )
ovmpog.3 ⊢ 𝐹 = ( 𝑥 ∈ 𝐶 , 𝑦 ∈ 𝐷 ↦ 𝑅 )
Assertion ovmpog ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ∧ 𝑆 ∈ 𝐻 ) → ( 𝐴 𝐹 𝐵 ) = 𝑆 )

Proof

Step Hyp Ref Expression
1 ovmpog.1 ⊢ ( 𝑥 = 𝐴 → 𝑅 = 𝐺 )
2 ovmpog.2 ⊢ ( 𝑦 = 𝐵 → 𝐺 = 𝑆 )
3 ovmpog.3 ⊢ 𝐹 = ( 𝑥 ∈ 𝐶 , 𝑦 ∈ 𝐷 ↦ 𝑅 )
4 1 2 sylan9eq ⊢ ( ( 𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ) → 𝑅 = 𝑆 )
5 4 3 ovmpoga ⊢ ( ( 𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ∧ 𝑆 ∈ 𝐻 ) → ( 𝐴 𝐹 𝐵 ) = 𝑆 )