Metamath Proof Explorer


Theorem pm2.65d

Description: Deduction for proof by contradiction. (Contributed by NM, 26-Jun-1994) (Proof shortened by Wolf Lammen, 26-May-2013)

Ref Expression
Hypotheses pm2.65d.1 ( 𝜑 → ( 𝜓𝜒 ) )
pm2.65d.2 ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) )
Assertion pm2.65d ( 𝜑 → ¬ 𝜓 )

Proof

Step Hyp Ref Expression
1 pm2.65d.1 ( 𝜑 → ( 𝜓𝜒 ) )
2 pm2.65d.2 ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) )
3 2 1 nsyld ( 𝜑 → ( 𝜓 → ¬ 𝜓 ) )
4 3 pm2.01d ( 𝜑 → ¬ 𝜓 )