Metamath Proof Explorer


Theorem prcliscplgr

Description: A proper class (representing a null graph, see vtxvalprc ) has the property of a complete graph (see also cplgr0v ), but cannot be an element of ComplGraph , of course. Because of this, a sethood antecedent like G e. W is necessary in the following theorems like iscplgr . (Contributed by AV, 14-Feb-2022)

Ref Expression
Hypothesis cplgruvtxb.v 𝑉 = ( Vtx ‘ 𝐺 )
Assertion prcliscplgr ( ¬ 𝐺 ∈ V → ∀ 𝑣𝑉 𝑣 ∈ ( UnivVtx ‘ 𝐺 ) )

Proof

Step Hyp Ref Expression
1 cplgruvtxb.v 𝑉 = ( Vtx ‘ 𝐺 )
2 fvprc ( ¬ 𝐺 ∈ V → ( Vtx ‘ 𝐺 ) = ∅ )
3 1 eqeq1i ( 𝑉 = ∅ ↔ ( Vtx ‘ 𝐺 ) = ∅ )
4 rzal ( 𝑉 = ∅ → ∀ 𝑣𝑉 𝑣 ∈ ( UnivVtx ‘ 𝐺 ) )
5 3 4 sylbir ( ( Vtx ‘ 𝐺 ) = ∅ → ∀ 𝑣𝑉 𝑣 ∈ ( UnivVtx ‘ 𝐺 ) )
6 2 5 syl ( ¬ 𝐺 ∈ V → ∀ 𝑣𝑉 𝑣 ∈ ( UnivVtx ‘ 𝐺 ) )