Metamath Proof Explorer


Theorem prdsvscaval

Description: Scalar multiplication in a structure product is pointwise. (Contributed by Stefan O'Rear, 10-Jan-2015)

Ref Expression
Hypotheses prdsbasmpt.y ⊢ 𝑌 = ( 𝑆 Xs 𝑅 )
prdsbasmpt.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
prdsvscaval.t ⊢ · = ( ·𝑠 ‘ 𝑌 )
prdsvscaval.k ⊢ 𝐾 = ( Base ‘ 𝑆 )
prdsvscaval.s ⊢ ( 𝜑 → 𝑆 ∈ 𝑉 )
prdsvscaval.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑊 )
prdsvscaval.r ⊢ ( 𝜑 → 𝑅 Fn 𝐼 )
prdsvscaval.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐾 )
prdsvscaval.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
Assertion prdsvscaval ( 𝜑 → ( 𝐹 · 𝐺 ) = ( 𝑥 ∈ 𝐼 ↦ ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) ) )

Proof

Step Hyp Ref Expression
1 prdsbasmpt.y ⊢ 𝑌 = ( 𝑆 Xs 𝑅 )
2 prdsbasmpt.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
3 prdsvscaval.t ⊢ · = ( ·𝑠 ‘ 𝑌 )
4 prdsvscaval.k ⊢ 𝐾 = ( Base ‘ 𝑆 )
5 prdsvscaval.s ⊢ ( 𝜑 → 𝑆 ∈ 𝑉 )
6 prdsvscaval.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑊 )
7 prdsvscaval.r ⊢ ( 𝜑 → 𝑅 Fn 𝐼 )
8 prdsvscaval.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐾 )
9 prdsvscaval.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
10 fnex ⊢ ( ( 𝑅 Fn 𝐼 ∧ 𝐼 ∈ 𝑊 ) → 𝑅 ∈ V )
11 7 6 10 syl2anc ⊢ ( 𝜑 → 𝑅 ∈ V )
12 7 fndmd ⊢ ( 𝜑 → dom 𝑅 = 𝐼 )
13 1 5 11 2 12 4 3 prdsvsca ⊢ ( 𝜑 → · = ( 𝑦 ∈ 𝐾 , 𝑧 ∈ 𝐵 ↦ ( 𝑥 ∈ 𝐼 ↦ ( 𝑦 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝑧 ‘ 𝑥 ) ) ) ) )
14 id ⊢ ( 𝑦 = 𝐹 → 𝑦 = 𝐹 )
15 fveq1 ⊢ ( 𝑧 = 𝐺 → ( 𝑧 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑥 ) )
16 14 15 oveqan12d ⊢ ( ( 𝑦 = 𝐹 ∧ 𝑧 = 𝐺 ) → ( 𝑦 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝑧 ‘ 𝑥 ) ) = ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) )
17 16 adantl ⊢ ( ( 𝜑 ∧ ( 𝑦 = 𝐹 ∧ 𝑧 = 𝐺 ) ) → ( 𝑦 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝑧 ‘ 𝑥 ) ) = ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) )
18 17 mpteq2dv ⊢ ( ( 𝜑 ∧ ( 𝑦 = 𝐹 ∧ 𝑧 = 𝐺 ) ) → ( 𝑥 ∈ 𝐼 ↦ ( 𝑦 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝑧 ‘ 𝑥 ) ) ) = ( 𝑥 ∈ 𝐼 ↦ ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) ) )
19 6 mptexd ⊢ ( 𝜑 → ( 𝑥 ∈ 𝐼 ↦ ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) ) ∈ V )
20 13 18 8 9 19 ovmpod ⊢ ( 𝜑 → ( 𝐹 · 𝐺 ) = ( 𝑥 ∈ 𝐼 ↦ ( 𝐹 ( ·𝑠 ‘ ( 𝑅 ‘ 𝑥 ) ) ( 𝐺 ‘ 𝑥 ) ) ) )