Metamath Proof Explorer


Theorem prdsvscaval

Description: Scalar multiplication in a structure product is pointwise. (Contributed by Stefan O'Rear, 10-Jan-2015)

Ref Expression
Hypotheses prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
prdsbasmpt.b ⊢ B = Base Y
prdsvscaval.t ⊢ · ˙ = ⋅ Y
prdsvscaval.k ⊢ K = Base S
prdsvscaval.s ⊢ φ → S ∈ V
prdsvscaval.i ⊢ φ → I ∈ W
prdsvscaval.r ⊢ φ → R Fn I
prdsvscaval.f ⊢ φ → F ∈ K
prdsvscaval.g ⊢ φ → G ∈ B
Assertion prdsvscaval ⊢ φ → F · ˙ G = x ∈ I ⟼ F ⋅ R ⁡ x G ⁡ x

Proof

Step Hyp Ref Expression
1 prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
2 prdsbasmpt.b ⊢ B = Base Y
3 prdsvscaval.t ⊢ · ˙ = ⋅ Y
4 prdsvscaval.k ⊢ K = Base S
5 prdsvscaval.s ⊢ φ → S ∈ V
6 prdsvscaval.i ⊢ φ → I ∈ W
7 prdsvscaval.r ⊢ φ → R Fn I
8 prdsvscaval.f ⊢ φ → F ∈ K
9 prdsvscaval.g ⊢ φ → G ∈ B
10 fnex ⊢ R Fn I ∧ I ∈ W → R ∈ V
11 7 6 10 syl2anc ⊢ φ → R ∈ V
12 7 fndmd ⊢ φ → dom ⁡ R = I
13 1 5 11 2 12 4 3 prdsvsca ⊢ φ → · ˙ = y ∈ K , z ∈ B ⟼ x ∈ I ⟼ y ⋅ R ⁡ x z ⁡ x
14 id ⊢ y = F → y = F
15 fveq1 ⊢ z = G → z ⁡ x = G ⁡ x
16 14 15 oveqan12d ⊢ y = F ∧ z = G → y ⋅ R ⁡ x z ⁡ x = F ⋅ R ⁡ x G ⁡ x
17 16 adantl ⊢ φ ∧ y = F ∧ z = G → y ⋅ R ⁡ x z ⁡ x = F ⋅ R ⁡ x G ⁡ x
18 17 mpteq2dv ⊢ φ ∧ y = F ∧ z = G → x ∈ I ⟼ y ⋅ R ⁡ x z ⁡ x = x ∈ I ⟼ F ⋅ R ⁡ x G ⁡ x
19 6 mptexd ⊢ φ → x ∈ I ⟼ F ⋅ R ⁡ x G ⁡ x ∈ V
20 13 18 8 9 19 ovmpod ⊢ φ → F · ˙ G = x ∈ I ⟼ F ⋅ R ⁡ x G ⁡ x