Metamath Proof Explorer


Theorem pw2divsidd

Description: Identity law for division over powers of two. (Contributed by Scott Fenton, 21-Feb-2026)

Ref Expression
Hypothesis pw2divs0d.1 ⊢ ( 𝜑 → 𝑁 ∈ ℕ0s )
Assertion pw2divsidd ( 𝜑 → ( ( 2s ↑s 𝑁 ) /su ( 2s ↑s 𝑁 ) ) = 1s )

Proof

Step Hyp Ref Expression
1 pw2divs0d.1 ⊢ ( 𝜑 → 𝑁 ∈ ℕ0s )
2 2no ⊢ 2s ∈ No
3 expscl ⊢ ( ( 2s ∈ No ∧ 𝑁 ∈ ℕ0s ) → ( 2s ↑s 𝑁 ) ∈ No )
4 2 1 3 sylancr ⊢ ( 𝜑 → ( 2s ↑s 𝑁 ) ∈ No )
5 4 mulsridd ⊢ ( 𝜑 → ( ( 2s ↑s 𝑁 ) ·s 1s ) = ( 2s ↑s 𝑁 ) )
6 1no ⊢ 1s ∈ No
7 6 a1i ⊢ ( 𝜑 → 1s ∈ No )
8 4 7 1 pw2divmulsd ⊢ ( 𝜑 → ( ( ( 2s ↑s 𝑁 ) /su ( 2s ↑s 𝑁 ) ) = 1s ↔ ( ( 2s ↑s 𝑁 ) ·s 1s ) = ( 2s ↑s 𝑁 ) ) )
9 5 8 mpbird ⊢ ( 𝜑 → ( ( 2s ↑s 𝑁 ) /su ( 2s ↑s 𝑁 ) ) = 1s )