Metamath Proof Explorer
Description: Equality theorem for quotient set, deduction form. (Contributed by Steven Nguyen, 30-Apr-2023)
|
|
Ref |
Expression |
|
Hypotheses |
qseq12d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
|
qseq12d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
|
Assertion |
qseq12d |
⊢ ( 𝜑 → ( 𝐴 / 𝐶 ) = ( 𝐵 / 𝐷 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
qseq12d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
2 |
|
qseq12d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
3 |
|
qseq12 |
⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 / 𝐶 ) = ( 𝐵 / 𝐷 ) ) |
4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → ( 𝐴 / 𝐶 ) = ( 𝐵 / 𝐷 ) ) |