Metamath Proof Explorer


Theorem rab0OLD

Description: Obsolete version of rab0 as of 10-Jun-2026. (Contributed by NM, 15-Oct-2003) (Proof shortened by Andrew Salmon, 26-Jun-2011) (Proof shortened by JJ, 14-Jul-2021) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion rab0OLD { 𝑥 ∈ ∅ ∣ 𝜑 } = ∅

Proof

Step Hyp Ref Expression
1 df-rab { 𝑥 ∈ ∅ ∣ 𝜑 } = { 𝑥 ∣ ( 𝑥 ∈ ∅ ∧ 𝜑 ) }
2 ab0 ( { 𝑥 ∣ ( 𝑥 ∈ ∅ ∧ 𝜑 ) } = ∅ ↔ ∀ 𝑥 ¬ ( 𝑥 ∈ ∅ ∧ 𝜑 ) )
3 noel ¬ 𝑥 ∈ ∅
4 3 intnanr ¬ ( 𝑥 ∈ ∅ ∧ 𝜑 )
5 2 4 mpgbir { 𝑥 ∣ ( 𝑥 ∈ ∅ ∧ 𝜑 ) } = ∅
6 1 5 eqtri { 𝑥 ∈ ∅ ∣ 𝜑 } = ∅