Metamath Proof Explorer


Theorem rabbidva2

Description: Equivalent wff's yield equal restricted class abstractions. (Contributed by Thierry Arnoux, 4-Feb-2017)

Ref Expression
Hypothesis rabbidva2.1 ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑥 ∈ 𝐵 ∧ 𝜒 ) ) )
Assertion rabbidva2 ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∈ 𝐵 ∣ 𝜒 } )

Proof

Step Hyp Ref Expression
1 rabbidva2.1 ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑥 ∈ 𝐵 ∧ 𝜒 ) ) )
2 1 abbidv ⊢ ( 𝜑 → { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) } = { 𝑥 ∣ ( 𝑥 ∈ 𝐵 ∧ 𝜒 ) } )
3 df-rab ⊢ { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) }
4 df-rab ⊢ { 𝑥 ∈ 𝐵 ∣ 𝜒 } = { 𝑥 ∣ ( 𝑥 ∈ 𝐵 ∧ 𝜒 ) }
5 2 3 4 3eqtr4g ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∈ 𝐵 ∣ 𝜒 } )