Metamath Proof Explorer


Theorem ralsanmo

Description: An "all some" statement restricted to a class, conjoined with the claim that at most one x in A satisfies its antecedent, is equivalent to the universal part conjoined with the claim that exactly one x in A satisfies the antecedent. This is the restricted counterpart of alsanmo . (Contributed by Peter Mazsa and David A. Wheeler, 20-Jul-2026)

Ref Expression
Assertion ralsanmo ( ( ∀∃ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) )

Proof

Step Hyp Ref Expression
1 df-rals ⊢ ( ∀∃ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) )
2 1 anbi1i ⊢ ( ( ∀∃ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) )
3 anass ⊢ ( ( ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 ∈ 𝐴 𝜑 ) ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ( ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ) )
4 reu5 ⊢ ( ∃! 𝑥 ∈ 𝐴 𝜑 ↔ ( ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) )
5 4 bicomi ⊢ ( ( ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ↔ ∃! 𝑥 ∈ 𝐴 𝜑 )
6 5 anbi2i ⊢ ( ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ( ∃ 𝑥 ∈ 𝐴 𝜑 ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) )
7 2 3 6 3bitri ⊢ ( ( ∀∃ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃* 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) )