Metamath Proof Explorer


Theorem ralseubii

Description: Congruence for "all some one" restricted to a class. This is the "all some one" counterpart of ralsbii . (Contributed by David A. Wheeler, 21-Jul-2026)

Ref Expression
Hypotheses ralseubii.1 ⊢ ( 𝜑 ↔ 𝜒 )
ralseubii.2 ⊢ ( 𝜓 ↔ 𝜃 )
Assertion ralseubii ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀∃! 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) )

Proof

Step Hyp Ref Expression
1 ralseubii.1 ⊢ ( 𝜑 ↔ 𝜒 )
2 ralseubii.2 ⊢ ( 𝜓 ↔ 𝜃 )
3 1 2 imbi12i ⊢ ( ( 𝜑 → 𝜓 ) ↔ ( 𝜒 → 𝜃 ) )
4 3 ralbii ⊢ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀ 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) )
5 1 reubii ⊢ ( ∃! 𝑥 ∈ 𝐴 𝜑 ↔ ∃! 𝑥 ∈ 𝐴 𝜒 )
6 4 5 anbi12i ⊢ ( ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜒 ) )
7 df-ralseu ⊢ ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) )
8 df-ralseu ⊢ ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜒 ) )
9 6 7 8 3bitr4i ⊢ ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀∃! 𝑥 ∈ 𝐴 ( 𝜒 → 𝜃 ) )