Metamath Proof Explorer


Theorem rebase

Description: The base of the field of reals. (Contributed by Thierry Arnoux, 1-Nov-2017)

Ref Expression
Assertion rebase ℝ = ( Base ‘ ℝfld )

Proof

Step Hyp Ref Expression
1 ax-resscn ℝ ⊆ ℂ
2 df-refld fld = ( ℂflds ℝ )
3 cnfldbas ℂ = ( Base ‘ ℂfld )
4 2 3 ressbas2 ( ℝ ⊆ ℂ → ℝ = ( Base ‘ ℝfld ) )
5 1 4 ax-mp ℝ = ( Base ‘ ℝfld )