Metamath Proof Explorer


Theorem resclunitintvd

Description: Restrict continuous function on closed unit interval. (Contributed by metakunt, 12-May-2024)

Ref Expression
Hypothesis resclunitintvd.1 ⊢ ( 𝜑 → ( 𝑥 ∈ ℂ ↦ 𝐴 ) ∈ ( ℂ –cn→ ℂ ) )
Assertion resclunitintvd ( 𝜑 → ( 𝑥 ∈ ( 0 [,] 1 ) ↦ 𝐴 ) ∈ ( ( 0 [,] 1 ) –cn→ ℂ ) )

Proof

Step Hyp Ref Expression
1 resclunitintvd.1 ⊢ ( 𝜑 → ( 𝑥 ∈ ℂ ↦ 𝐴 ) ∈ ( ℂ –cn→ ℂ ) )
2 unitsscn ⊢ ( 0 [,] 1 ) ⊆ ℂ
3 resmpt ⊢ ( ( 0 [,] 1 ) ⊆ ℂ → ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ↾ ( 0 [,] 1 ) ) = ( 𝑥 ∈ ( 0 [,] 1 ) ↦ 𝐴 ) )
4 2 3 ax-mp ⊢ ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ↾ ( 0 [,] 1 ) ) = ( 𝑥 ∈ ( 0 [,] 1 ) ↦ 𝐴 )
5 rescncf ⊢ ( ( 0 [,] 1 ) ⊆ ℂ → ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ∈ ( ℂ –cn→ ℂ ) → ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ↾ ( 0 [,] 1 ) ) ∈ ( ( 0 [,] 1 ) –cn→ ℂ ) ) )
6 2 5 ax-mp ⊢ ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ∈ ( ℂ –cn→ ℂ ) → ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ↾ ( 0 [,] 1 ) ) ∈ ( ( 0 [,] 1 ) –cn→ ℂ ) )
7 1 6 syl ⊢ ( 𝜑 → ( ( 𝑥 ∈ ℂ ↦ 𝐴 ) ↾ ( 0 [,] 1 ) ) ∈ ( ( 0 [,] 1 ) –cn→ ℂ ) )
8 4 7 eqeltrrid ⊢ ( 𝜑 → ( 𝑥 ∈ ( 0 [,] 1 ) ↦ 𝐴 ) ∈ ( ( 0 [,] 1 ) –cn→ ℂ ) )