Metamath Proof Explorer


Theorem resclunitintvd

Description: Restrict continuous function on closed unit interval. (Contributed by metakunt, 12-May-2024)

Ref Expression
Hypothesis resclunitintvd.1 ⊢ φ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
Assertion resclunitintvd ⊢ φ → x ∈ 0 1 ⟼ A : 0 1 ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 resclunitintvd.1 ⊢ φ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
2 unitsscn ⊢ 0 1 ⊆ ℂ
3 resmpt ⊢ 0 1 ⊆ ℂ → x ∈ ℂ ⟼ A ↾ 0 1 = x ∈ 0 1 ⟼ A
4 2 3 ax-mp ⊢ x ∈ ℂ ⟼ A ↾ 0 1 = x ∈ 0 1 ⟼ A
5 rescncf ⊢ 0 1 ⊆ ℂ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ → x ∈ ℂ ⟼ A ↾ 0 1 : 0 1 ⟶cn ℂ
6 2 5 ax-mp ⊢ x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ → x ∈ ℂ ⟼ A ↾ 0 1 : 0 1 ⟶cn ℂ
7 1 6 syl ⊢ φ → x ∈ ℂ ⟼ A ↾ 0 1 : 0 1 ⟶cn ℂ
8 4 7 eqeltrrid ⊢ φ → x ∈ 0 1 ⟼ A : 0 1 ⟶cn ℂ