Metamath Proof Explorer


Theorem reseq1

Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994)

Ref Expression
Assertion reseq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )

Proof

Step Hyp Ref Expression
1 ineq1 ( 𝐴 = 𝐵 → ( 𝐴 ∩ ( 𝐶 × V ) ) = ( 𝐵 ∩ ( 𝐶 × V ) ) )
2 df-res ( 𝐴𝐶 ) = ( 𝐴 ∩ ( 𝐶 × V ) )
3 df-res ( 𝐵𝐶 ) = ( 𝐵 ∩ ( 𝐶 × V ) )
4 1 2 3 3eqtr4g ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )