Metamath Proof Explorer


Theorem reximddv2

Description: Double deduction from Theorem 19.22 of Margaris p. 90. (Contributed by Thierry Arnoux, 15-Dec-2019)

Ref Expression
Hypotheses reximddv2.1 ⊢ ( ( ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑦 ∈ 𝐵 ) ∧ 𝜓 ) → 𝜒 )
reximddv2.2 ⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜓 )
Assertion reximddv2 ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜒 )

Proof

Step Hyp Ref Expression
1 reximddv2.1 ⊢ ( ( ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑦 ∈ 𝐵 ) ∧ 𝜓 ) → 𝜒 )
2 reximddv2.2 ⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜓 )
3 1 ex ⊢ ( ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑦 ∈ 𝐵 ) → ( 𝜓 → 𝜒 ) )
4 3 reximdva ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( ∃ 𝑦 ∈ 𝐵 𝜓 → ∃ 𝑦 ∈ 𝐵 𝜒 ) )
5 4 impr ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝐴 ∧ ∃ 𝑦 ∈ 𝐵 𝜓 ) ) → ∃ 𝑦 ∈ 𝐵 𝜒 )
6 5 2 reximddv ⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 𝜒 )