Metamath Proof Explorer


Theorem rhm0

Description: A ring homomorphism preserves 0 . (Contributed by Jeff Madsen, 2-Jan-2011) (Revised by AV, 23-Jul-2026)

Ref Expression
Hypotheses rhm0.0 0 = ( 0g𝑅 )
rhm0.z 𝑍 = ( 0g𝑆 )
Assertion rhm0 ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → ( 𝐹0 ) = 𝑍 )

Proof

Step Hyp Ref Expression
1 rhm0.0 0 = ( 0g𝑅 )
2 rhm0.z 𝑍 = ( 0g𝑆 )
3 rhmghm ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) )
4 ghmmhm ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) → 𝐹 ∈ ( 𝑅 MndHom 𝑆 ) )
5 1 2 mhm0 ( 𝐹 ∈ ( 𝑅 MndHom 𝑆 ) → ( 𝐹0 ) = 𝑍 )
6 3 4 5 3syl ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → ( 𝐹0 ) = 𝑍 )