Metamath Proof Explorer


Theorem rhm0

Description: A ring homomorphism preserves 0 . (Contributed by Jeff Madsen, 2-Jan-2011) (Revised by AV, 23-Jul-2026)

Ref Expression
Hypotheses rhm0.0
|- .0. = ( 0g ` R )
rhm0.z
|- Z = ( 0g ` S )
Assertion rhm0
|- ( F e. ( R RingHom S ) -> ( F ` .0. ) = Z )

Proof

Step Hyp Ref Expression
1 rhm0.0
 |-  .0. = ( 0g ` R )
2 rhm0.z
 |-  Z = ( 0g ` S )
3 rhmghm
 |-  ( F e. ( R RingHom S ) -> F e. ( R GrpHom S ) )
4 ghmmhm
 |-  ( F e. ( R GrpHom S ) -> F e. ( R MndHom S ) )
5 1 2 mhm0
 |-  ( F e. ( R MndHom S ) -> ( F ` .0. ) = Z )
6 3 4 5 3syl
 |-  ( F e. ( R RingHom S ) -> ( F ` .0. ) = Z )