Metamath Proof Explorer


Theorem ricref

Description: Ring isomorphism is reflexive. (Contributed by by AV, 24-Jul-2026)

Ref Expression
Assertion ricref ( 𝑅 ∈ Ring → 𝑅𝑟 𝑅 )

Proof

Step Hyp Ref Expression
1 eqid ( Base ‘ 𝑅 ) = ( Base ‘ 𝑅 )
2 1 idrhm ( 𝑅 ∈ Ring → ( I ↾ ( Base ‘ 𝑅 ) ) ∈ ( 𝑅 RingHom 𝑅 ) )
3 f1oi ( I ↾ ( Base ‘ 𝑅 ) ) : ( Base ‘ 𝑅 ) –1-1-onto→ ( Base ‘ 𝑅 )
4 1 1 isrim ( ( I ↾ ( Base ‘ 𝑅 ) ) ∈ ( 𝑅 RingIso 𝑅 ) ↔ ( ( I ↾ ( Base ‘ 𝑅 ) ) ∈ ( 𝑅 RingHom 𝑅 ) ∧ ( I ↾ ( Base ‘ 𝑅 ) ) : ( Base ‘ 𝑅 ) –1-1-onto→ ( Base ‘ 𝑅 ) ) )
5 2 3 4 sylanblrc ( 𝑅 ∈ Ring → ( I ↾ ( Base ‘ 𝑅 ) ) ∈ ( 𝑅 RingIso 𝑅 ) )
6 brrici ( ( I ↾ ( Base ‘ 𝑅 ) ) ∈ ( 𝑅 RingIso 𝑅 ) → 𝑅𝑟 𝑅 )
7 5 6 syl ( 𝑅 ∈ Ring → 𝑅𝑟 𝑅 )