Metamath Proof Explorer


Theorem riotaeqbidv

Description: Equality deduction for restricted universal quantifier. (Contributed by NM, 15-Sep-2011)

Ref Expression
Hypotheses riotaeqbidv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
riotaeqbidv.2 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion riotaeqbidv ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ∈ 𝐵 𝜒 ) )

Proof

Step Hyp Ref Expression
1 riotaeqbidv.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 riotaeqbidv.2 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
3 2 riotabidv ⊢ ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ∈ 𝐴 𝜒 ) )
4 1 riotaeqdv ⊢ ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜒 ) = ( ℩ 𝑥 ∈ 𝐵 𝜒 ) )
5 3 4 eqtrd ⊢ ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ∈ 𝐵 𝜒 ) )