Metamath Proof Explorer


Theorem riotabidv

Description: Formula-building deduction for restricted iota. (Contributed by NM, 15-Sep-2011)

Ref Expression
Hypothesis riotabidv.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion riotabidv ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ∈ 𝐴 𝜒 ) )

Proof

Step Hyp Ref Expression
1 riotabidv.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 1 anbi2d ⊢ ( 𝜑 → ( ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑥 ∈ 𝐴 ∧ 𝜒 ) ) )
3 2 iotabidv ⊢ ( 𝜑 → ( ℩ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) ) = ( ℩ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜒 ) ) )
4 df-riota ⊢ ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) )
5 df-riota ⊢ ( ℩ 𝑥 ∈ 𝐴 𝜒 ) = ( ℩ 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜒 ) )
6 3 4 5 3eqtr4g ⊢ ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 𝜓 ) = ( ℩ 𝑥 ∈ 𝐴 𝜒 ) )