Metamath Proof Explorer


Theorem rsp3

Description: From a restricted universal statement over A , specialize to an arbitrary element y e. A , cf. rsp . (Contributed by Peter Mazsa, 9-Feb-2026)

Ref Expression
Hypotheses rsp3.1 ⊢ Ⅎ 𝑥 𝐴
rsp3.2 ⊢ Ⅎ 𝑦 𝐴
rsp3.3 ⊢ Ⅎ 𝑦 𝜑
rsp3.4 ⊢ Ⅎ 𝑥 𝜓
rsp3.5 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
Assertion rsp3 ( ∀ 𝑥 ∈ 𝐴 𝜑 → ( 𝑦 ∈ 𝐴 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 rsp3.1 ⊢ Ⅎ 𝑥 𝐴
2 rsp3.2 ⊢ Ⅎ 𝑦 𝐴
3 rsp3.3 ⊢ Ⅎ 𝑦 𝜑
4 rsp3.4 ⊢ Ⅎ 𝑥 𝜓
5 rsp3.5 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
6 1 2 3 4 5 cbvralfw ⊢ ( ∀ 𝑥 ∈ 𝐴 𝜑 ↔ ∀ 𝑦 ∈ 𝐴 𝜓 )
7 rsp ⊢ ( ∀ 𝑦 ∈ 𝐴 𝜓 → ( 𝑦 ∈ 𝐴 → 𝜓 ) )
8 6 7 sylbi ⊢ ( ∀ 𝑥 ∈ 𝐴 𝜑 → ( 𝑦 ∈ 𝐴 → 𝜓 ) )