Metamath Proof Explorer


Theorem rspa

Description: Restricted specialization. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Assertion rspa ( ( ∀ 𝑥 ∈ 𝐴 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝜑 )

Proof

Step Hyp Ref Expression
1 rsp ⊢ ( ∀ 𝑥 ∈ 𝐴 𝜑 → ( 𝑥 ∈ 𝐴 → 𝜑 ) )
2 1 imp ⊢ ( ( ∀ 𝑥 ∈ 𝐴 𝜑 ∧ 𝑥 ∈ 𝐴 ) → 𝜑 )