Metamath Proof Explorer


Theorem scottssr1

Description: Relationship between a Scott's trick set and the cumulative hierarchy. (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion scottssr1 ( 𝐴𝐵 → Scott 𝐵 ⊆ ( 𝑅1 ‘ suc ( rank ‘ 𝐴 ) ) )

Proof

Step Hyp Ref Expression
1 rankscottu ( 𝐴𝐵 → ( rank ‘ Scott 𝐵 ) ⊆ suc ( rank ‘ 𝐴 ) )
2 rankon ( rank ‘ 𝐴 ) ∈ On
3 2 onsuci suc ( rank ‘ 𝐴 ) ∈ On
4 scottex2 Scott 𝐵 ∈ V
5 4 rankr1b ( suc ( rank ‘ 𝐴 ) ∈ On → ( Scott 𝐵 ⊆ ( 𝑅1 ‘ suc ( rank ‘ 𝐴 ) ) ↔ ( rank ‘ Scott 𝐵 ) ⊆ suc ( rank ‘ 𝐴 ) ) )
6 3 5 ax-mp ( Scott 𝐵 ⊆ ( 𝑅1 ‘ suc ( rank ‘ 𝐴 ) ) ↔ ( rank ‘ Scott 𝐵 ) ⊆ suc ( rank ‘ 𝐴 ) )
7 1 6 sylibr ( 𝐴𝐵 → Scott 𝐵 ⊆ ( 𝑅1 ‘ suc ( rank ‘ 𝐴 ) ) )