Metamath Proof Explorer


Theorem shsva

Description: Vector sum belongs to subspace sum. (Contributed by NM, 15-Dec-2004) (New usage is discouraged.)

Ref Expression
Assertion shsva ( ( 𝐴 ∈ Sℋ ∧ 𝐵 ∈ Sℋ ) → ( ( 𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐵 ) → ( 𝐶 +ℎ 𝐷 ) ∈ ( 𝐴 +ℋ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 eqid ⊢ ( 𝐶 +ℎ 𝐷 ) = ( 𝐶 +ℎ 𝐷 )
2 rspceov ⊢ ( ( 𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐵 ∧ ( 𝐶 +ℎ 𝐷 ) = ( 𝐶 +ℎ 𝐷 ) ) → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 ( 𝐶 +ℎ 𝐷 ) = ( 𝑥 +ℎ 𝑦 ) )
3 1 2 mp3an3 ⊢ ( ( 𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐵 ) → ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 ( 𝐶 +ℎ 𝐷 ) = ( 𝑥 +ℎ 𝑦 ) )
4 shsel ⊢ ( ( 𝐴 ∈ Sℋ ∧ 𝐵 ∈ Sℋ ) → ( ( 𝐶 +ℎ 𝐷 ) ∈ ( 𝐴 +ℋ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐴 ∃ 𝑦 ∈ 𝐵 ( 𝐶 +ℎ 𝐷 ) = ( 𝑥 +ℎ 𝑦 ) ) )
5 3 4 imbitrrid ⊢ ( ( 𝐴 ∈ Sℋ ∧ 𝐵 ∈ Sℋ ) → ( ( 𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐵 ) → ( 𝐶 +ℎ 𝐷 ) ∈ ( 𝐴 +ℋ 𝐵 ) ) )