Metamath Proof Explorer


Theorem sigagenss2

Description: Sufficient condition for inclusion of sigma-algebras. This is used to prove equality of sigma-algebras. (Contributed by Thierry Arnoux, 10-Oct-2017)

Ref Expression
Assertion sigagenss2 ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( sigaGen ‘ 𝐴 ) ⊆ ( sigaGen ‘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 sigagensiga ⊢ ( 𝐵 ∈ 𝑉 → ( sigaGen ‘ 𝐵 ) ∈ ( sigAlgebra ‘ ∪ 𝐵 ) )
2 1 3ad2ant3 ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( sigaGen ‘ 𝐵 ) ∈ ( sigAlgebra ‘ ∪ 𝐵 ) )
3 simp1 ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ∪ 𝐴 = ∪ 𝐵 )
4 3 fveq2d ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( sigAlgebra ‘ ∪ 𝐴 ) = ( sigAlgebra ‘ ∪ 𝐵 ) )
5 2 4 eleqtrrd ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( sigaGen ‘ 𝐵 ) ∈ ( sigAlgebra ‘ ∪ 𝐴 ) )
6 simp2 ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) )
7 sigagenss ⊢ ( ( ( sigaGen ‘ 𝐵 ) ∈ ( sigAlgebra ‘ ∪ 𝐴 ) ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ) → ( sigaGen ‘ 𝐴 ) ⊆ ( sigaGen ‘ 𝐵 ) )
8 5 6 7 syl2anc ⊢ ( ( ∪ 𝐴 = ∪ 𝐵 ∧ 𝐴 ⊆ ( sigaGen ‘ 𝐵 ) ∧ 𝐵 ∈ 𝑉 ) → ( sigaGen ‘ 𝐴 ) ⊆ ( sigaGen ‘ 𝐵 ) )