Metamath Proof Explorer


Theorem sltsd

Description: Deduce surreal set less-than. (Contributed by Scott Fenton, 24-Sep-2024)

Ref Expression
Hypotheses sltsd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
sltsd.2 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
sltsd.3 ⊢ ( 𝜑 → 𝐴 ⊆ No )
sltsd.4 ⊢ ( 𝜑 → 𝐵 ⊆ No )
sltsd.5 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵 ) → 𝑥 <s 𝑦 )
Assertion sltsd ( 𝜑 → 𝐴 <<s 𝐵 )

Proof

Step Hyp Ref Expression
1 sltsd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
2 sltsd.2 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
3 sltsd.3 ⊢ ( 𝜑 → 𝐴 ⊆ No )
4 sltsd.4 ⊢ ( 𝜑 → 𝐵 ⊆ No )
5 sltsd.5 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵 ) → 𝑥 <s 𝑦 )
6 1 elexd ⊢ ( 𝜑 → 𝐴 ∈ V )
7 2 elexd ⊢ ( 𝜑 → 𝐵 ∈ V )
8 5 3expb ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵 ) ) → 𝑥 <s 𝑦 )
9 8 ralrimivva ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 )
10 3 4 9 3jca ⊢ ( 𝜑 → ( 𝐴 ⊆ No ∧ 𝐵 ⊆ No ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 ) )
11 brslts ⊢ ( 𝐴 <<s 𝐵 ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ ( 𝐴 ⊆ No ∧ 𝐵 ⊆ No ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 ) ) )
12 6 7 10 11 syl21anbrc ⊢ ( 𝜑 → 𝐴 <<s 𝐵 )