Metamath Proof Explorer


Theorem sltssepc

Description: Two elements of separated sets obey less-than. (Contributed by Scott Fenton, 20-Aug-2024)

Ref Expression
Assertion sltssepc ( ( 𝐴 <<s 𝐵 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) → 𝑋 <s 𝑌 )

Proof

Step Hyp Ref Expression
1 sltssep ⊢ ( 𝐴 <<s 𝐵 → ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 )
2 breq1 ⊢ ( 𝑥 = 𝑋 → ( 𝑥 <s 𝑦 ↔ 𝑋 <s 𝑦 ) )
3 breq2 ⊢ ( 𝑦 = 𝑌 → ( 𝑋 <s 𝑦 ↔ 𝑋 <s 𝑌 ) )
4 2 3 rspc2va ⊢ ( ( ( 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 ) → 𝑋 <s 𝑌 )
5 4 ancoms ⊢ ( ( ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐵 𝑥 <s 𝑦 ∧ ( 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) ) → 𝑋 <s 𝑌 )
6 1 5 sylan ⊢ ( ( 𝐴 <<s 𝐵 ∧ ( 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) ) → 𝑋 <s 𝑌 )
7 6 3impb ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) → 𝑋 <s 𝑌 )