Metamath Proof Explorer


Theorem sltssepcd

Description: Two elements of separated sets obey less-than. Deduction form of sltssepc . (Contributed by Scott Fenton, 25-Sep-2024)

Ref Expression
Hypotheses sltssepcd.1 ⊢ ( 𝜑 → 𝐴 <<s 𝐵 )
sltssepcd.2 ⊢ ( 𝜑 → 𝑋 ∈ 𝐴 )
sltssepcd.3 ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
Assertion sltssepcd ( 𝜑 → 𝑋 <s 𝑌 )

Proof

Step Hyp Ref Expression
1 sltssepcd.1 ⊢ ( 𝜑 → 𝐴 <<s 𝐵 )
2 sltssepcd.2 ⊢ ( 𝜑 → 𝑋 ∈ 𝐴 )
3 sltssepcd.3 ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
4 sltssepc ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐵 ) → 𝑋 <s 𝑌 )
5 1 2 3 4 syl3anc ⊢ ( 𝜑 → 𝑋 <s 𝑌 )