Metamath Proof Explorer


Theorem spcedv

Description: Existential specialization, using implicit substitution, deduction version. (Contributed by RP, 12-Aug-2020) (Revised by AV, 16-Aug-2024)

Ref Expression
Hypotheses spcedv.1 ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
spcedv.2 ⊢ ( 𝜑 → 𝜒 )
spcedv.3 ⊢ ( 𝑥 = 𝑋 → ( 𝜓 ↔ 𝜒 ) )
Assertion spcedv ( 𝜑 → ∃ 𝑥 𝜓 )

Proof

Step Hyp Ref Expression
1 spcedv.1 ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 )
2 spcedv.2 ⊢ ( 𝜑 → 𝜒 )
3 spcedv.3 ⊢ ( 𝑥 = 𝑋 → ( 𝜓 ↔ 𝜒 ) )
4 3 spcegv ⊢ ( 𝑋 ∈ 𝑉 → ( 𝜒 → ∃ 𝑥 𝜓 ) )
5 1 2 4 sylc ⊢ ( 𝜑 → ∃ 𝑥 𝜓 )