Metamath Proof Explorer


Theorem sselid

Description: Membership inference from subclass relationship. (Contributed by NM, 25-Jun-2014)

Ref Expression
Hypotheses sseli.1 ⊢ 𝐴 ⊆ 𝐵
sselid.2 ⊢ ( 𝜑 → 𝐶 ∈ 𝐴 )
Assertion sselid ( 𝜑 → 𝐶 ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 sseli.1 ⊢ 𝐴 ⊆ 𝐵
2 sselid.2 ⊢ ( 𝜑 → 𝐶 ∈ 𝐴 )
3 1 sseli ⊢ ( 𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵 )
4 2 3 syl ⊢ ( 𝜑 → 𝐶 ∈ 𝐵 )