Metamath Proof Explorer


Theorem ssintab

Description: Subclass of the intersection of a class abstraction. (Contributed by NM, 31-Jul-2006) (Proof shortened by Andrew Salmon, 9-Jul-2011)

Ref Expression
Assertion ssintab ( 𝐴 ⊆ ∩ { 𝑥 ∣ 𝜑 } ↔ ∀ 𝑥 ( 𝜑 → 𝐴 ⊆ 𝑥 ) )

Proof

Step Hyp Ref Expression
1 ssint ⊢ ( 𝐴 ⊆ ∩ { 𝑥 ∣ 𝜑 } ↔ ∀ 𝑦 ∈ { 𝑥 ∣ 𝜑 } 𝐴 ⊆ 𝑦 )
2 sseq2 ⊢ ( 𝑦 = 𝑥 → ( 𝐴 ⊆ 𝑦 ↔ 𝐴 ⊆ 𝑥 ) )
3 2 ralab2 ⊢ ( ∀ 𝑦 ∈ { 𝑥 ∣ 𝜑 } 𝐴 ⊆ 𝑦 ↔ ∀ 𝑥 ( 𝜑 → 𝐴 ⊆ 𝑥 ) )
4 1 3 bitri ⊢ ( 𝐴 ⊆ ∩ { 𝑥 ∣ 𝜑 } ↔ ∀ 𝑥 ( 𝜑 → 𝐴 ⊆ 𝑥 ) )