Metamath Proof Explorer


Theorem ssriv

Description: Inference based on subclass definition. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypothesis ssriv.1 ⊢ ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 )
Assertion ssriv 𝐴 ⊆ 𝐵

Proof

Step Hyp Ref Expression
1 ssriv.1 ⊢ ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 )
2 df-ss ⊢ ( 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
3 2 1 mpgbir ⊢ 𝐴 ⊆ 𝐵